| Rules
Before you start to factor any polynomial problem, there are two things
you need to check. First, check to make sure the polynomial is in descending
order of degree, such as x2 + 7x +12.
Second, make sure there is no common monomial that you can factor out
of the polynomial. Here is an example:
3x3 + 21x2 + 36
Each term in this polynomial is divisible by 3x, so we remove 3x. Divide
each term by 3x. Here is what it will look like:
3x (x2 + 7x +12)
Once you have done those two things, you are ready to begin factoring.
Simple Polynomials
Factoring quadratic polynomials is not as hard as it may seem at first.
The best way to tackle this concept is to start with an easy one, then
work your way to harder, more advanced problems.
Here is a simple polynomial:
x2 + 7x + 12
Notice that there is no coefficient in the first term of the polynomial.
When there is no coefficient in the first term, factoring begins with
listing all of the factors of the last term as such:
Factors of +12
1 x 12, -1 x –12
2 x 6, -2 x –6
3 x 4, -3 x –4
Once you have all of the possible factors, find the pair that adds together
to get the coefficient of the second term. In this example, 3 + 4 = 7.
These two numbers will be the factors you will use. The answer to this
problem is (x + 4) (x + 3). If you check the problem using the FOIL method,
you will find that the answer does indeed result in
x2 + 7x + 12.
The same works if you have negative numbers in the equation, such as
x2 – 2x – 24. You do the process the same way, by starting
with listing the factors of the final term, but note that this time you
are listing the factors of a negative number.
Factors of – 24
1 ×–24, -1 x 24
2 x –12, -2 x 12
3 x – 8, -3 x 8
4 x –6, -4 x 6
Again, choose the factors that add up to the coefficient of the second
term. Notice that in this example, 4 + -6 = -2. The signs are very important,
as the answer to the problem is
(x + 4) (x – 6). If the signs were reversed, the problem would be
incorrect.
Example 1: x2 - 9x + 20
Start by listing the factors of 20.
1 × 20, -1 ×–20
2 × 10, -2 ×–10
4 × 5, -4 ×–5
Find the factors of 20 that add up to be –9. They are –4
x –5. Fill in the parenthesis.
(x – 4) (x – 5)
Example 2: x2 + 5x –36
List factors of –36
1 ×–36, -1 × 36
2 ×–18, -2 × 18
3 ×–12, -3 × 12
4 ×–9, -4 × 9
Choose the ones that add to be +5. They are –4 x 9. The answer
is (x – 4) (x + 9)
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More Complex Polynomials
When you add a coefficient in front of the first term, the problem becomes
more difficult, but certainly not impossible. Here is our example: 3x2
+17x +10. Like the previous problems, you start by listing the factors,
but this time of both the first and last terms:
Factors of 3
1 x 3
Factors of + 10
1 × 10, -1 ×–10
2 × 5, -2 ×–5 ×
Next, you have to simply start by guessing and checking. Start plugging
in factors. Then check by FOIL to see if you get the correct polynomial.
Note that you do not have to do the entire FOIL process, but you can skill
First and Last terms, and just simply multiply the Outer and Inner parts.
Since all of the terms in the example are positive, we only need to concern
ourselves with the positive factors. Here is an example:
(1x + 1) (3x + 10) = 3x2 + 13x + 10
Notice that the first and last terms are correct but the middle is not.
The first and last terms will always be correct, so you can skip finding
these, and just find the inner and outer terms. In this example, you would
do 1x times 10 and 1 times 3x. This gives you 10x + 3x, which is 13x and
not what we want (17x). Before moving to the next set of factors, rearrange
these and see if they work:
(1x + 10) (3x + 1)
Find Outer and Inner: 1x + 30x = 31x. Not what we want.
We can now eliminate 1 and 10 as possible solutions, since we tried them
in every possible order. Now move to the next factors of 10, 2 and 5
(3x + 5) (1x + 2)
Find Outer and Inner: 6x + 5x = 11x. Not what we want. Rearrange.
(3x + 2) (1x +5)
Find Outer and Inner: 15x + 2x = 17x. This is what we want. We have found
our solution. Check using FOIL and you get 3x2 + 17x +10.
You can use this same process, even if your first term is not prime.
The only difference is that you will have more chances to guess and check.
The key to finding the answer to complex polynomials is to be persistent.
If you have all of the factors listed, and if you try all possible combinations,
you will find the answer. Note that with experience, you can start to
get a feel for which factors are more likely to work out correctly. This
will speed up the process significantly.
Example 1: 4x2
+ 2x – 42
List the factors of 4. For the first term, just use positive factors.
4 × 1, 2 × 2
List the factors of –42
1 ×–42, -1 × 42, 2 ×–21, -2 ×
21, 3 ×–14, -3 × 14, 6 ×–7, -6 ×
7
Start guessing and checking. Usually the answer will not be factors
that are extremely different. Start with 6 x –7 and 2 ×
2: (2x + 6) (2x – 7)
Find the inner and outer terms: 12x – 14x = -2x.
This is the correct answer, but wrong sign. All you have to do
is switch the signs.
(2x – 6) (2x + 7)—check by doing inner and outer terms
-12x + 14x = 2x. This is the correct factorization.
Example 2: 2x2– 14x + 24
Since 2 is prime, the only factors are 1 x 2. List the factors
of 24. Since the middle term is negative, we need negative factors.
-1 ×–24, -2 ×–12, -3 ×–8, -4
×–6
Guess and check. Start with –3, -8
(2x – 3) (1x –8)
Find inner and outer terms: - 16x – 3x = -19x. Not right.
Switch –3 and –8.
(2x – 8) (1x – 3)
Find inner and outer terms: -6x – 8x = -14x. This is the
correct factorization.
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